1. ? % of 824 + 244 = 1480
1) 140
2) 150
3) 100
4) 180
5) 120
2. 24.5 × 8.4 × 16 = ?
1) 3292.8
2) 3492.8
3) 3294.8
4) 3192.8
5) 3094.8
Directions: In each of these questions, two equations numbered I and II with variables x and y are given.
1) 140
2) 150
3) 100
4) 180
5) 120
2. 24.5 × 8.4 × 16 = ?
1) 3292.8
2) 3492.8
3) 3294.8
4) 3192.8
5) 3094.8
Directions: In each of these questions, two equations numbered I and II with variables x and y are given.
You have to solve both the equations to find the value of x and y. Give answer:
1) if x > y
2) if x >= y
3) if x < y
4) if x <= y
5) if x = y or relationship between x and y cannot be determined.
3.
I. 2x^2 + 13x + 20 = 0
II. 2y^2 – 3y – 35 = 0
1) if x > y
2) if x >= y
3) if x < y
4) if x <= y
5) if x = y or relationship between x and y cannot be determined.
3.
I. 2x^2 + 13x + 20 = 0
II. 2y^2 – 3y – 35 = 0
I. 2x^2 + 8x + 5x + 20 = 0
(2x + 5) (x + 4) = 0 x = -5/2,– 4
II. 2y^2 – 10y + 7y – 35 = 0
(2y + 7) (y – 5) = 0 y = -7/2, 5
Relationship between x and y does not exist. 5) if x = y or relationship between x and y cannot be determined.
4.
I. 12x^2 – 41x + 35 = 0
II. 4y^2 – 17y +15 = 0
(2x + 5) (x + 4) = 0 x = -5/2,– 4
II. 2y^2 – 10y + 7y – 35 = 0
(2y + 7) (y – 5) = 0 y = -7/2, 5
Relationship between x and y does not exist. 5) if x = y or relationship between x and y cannot be determined.
4.
I. 12x^2 – 41x + 35 = 0
II. 4y^2 – 17y +15 = 0
I. 12x^2 – 20x – 21x + 35 = 0
(4x –7) (3x – 5) = 0
x = 7/4, 5/3
II. 4y^2 – 12y – 5y + 15 = 0 (4y – 5) (y – 3) = 0
y = 5/4, 3
Relationship between x and y does not exist
5) if x = y or relationship between x and y cannot be determined.
5.
I. 4x^2 – 4 = 60
II. 3y^2 + 3 = 51
(4x –7) (3x – 5) = 0
x = 7/4, 5/3
II. 4y^2 – 12y – 5y + 15 = 0 (4y – 5) (y – 3) = 0
y = 5/4, 3
Relationship between x and y does not exist
5) if x = y or relationship between x and y cannot be determined.
5.
I. 4x^2 – 4 = 60
II. 3y^2 + 3 = 51
5;
I. 4(x^2 – 1) = 60
x^2 – 1 = 15
x = +/- 4
II. 3(y^2 + 1) = 51
y^2 + 1 = 17
y = +/- 4 . 5) if x = y
6.
I. 28x^2 – 9x – 9 = 0
II. 7y^2 + 24y + 9 = 0
I. 4(x^2 – 1) = 60
x^2 – 1 = 15
x = +/- 4
II. 3(y^2 + 1) = 51
y^2 + 1 = 17
y = +/- 4 . 5) if x = y
6.
I. 28x^2 – 9x – 9 = 0
II. 7y^2 + 24y + 9 = 0
I. 28x^2 – 21x + 12x – 9 = 0
(7x + 3) (4x – 3) = 0
x = -3/7, 3/4
II. 7y^2 + 21y + 3y + 9 = 0
(7y + 3) (y + 3) = 0
y = -3/7,–3 2) if x >= y
Directions: In the following number series one number is wrong. Find out the wrong number.
7. 16, 40, 100, 250, 630
1) 630
2) 100
3) 250
4) 40
5) 16
(7x + 3) (4x – 3) = 0
x = -3/7, 3/4
II. 7y^2 + 21y + 3y + 9 = 0
(7y + 3) (y + 3) = 0
y = -3/7,–3 2) if x >= y
Directions: In the following number series one number is wrong. Find out the wrong number.
7. 16, 40, 100, 250, 630
1) 630
2) 100
3) 250
4) 40
5) 16
16 * 5/2 = 40
40 * 5/2 = 250
250 * 5/2 = 625 not equal to 630
8. 21, 48, 162, 969, 7748
1) 7748
2) 21
3) 969
4) 48
5) 162
40 * 5/2 = 250
250 * 5/2 = 625 not equal to 630
8. 21, 48, 162, 969, 7748
1) 7748
2) 21
3) 969
4) 48
5) 162
21 × 2 – 1 = 41 not equal to 48
41 × 4 – 2 = 162
162 × 6 – 3 = 969
969 × 8 – 4 = 7748
Hence, there should 41 in place of 48.
9. 118, 239, 96, 264, 68, 293
1) 293
2) 264
3) 96
4) 68
5) 239
41 × 4 – 2 = 162
162 × 6 – 3 = 969
969 × 8 – 4 = 7748
Hence, there should 41 in place of 48.
9. 118, 239, 96, 264, 68, 293
1) 293
2) 264
3) 96
4) 68
5) 239
118 + (11)^2 = 239
239 – (12)^2 = 95 not equal to 96
95 + (13)^2 = 264
264 – (14)^2 = 68
68 + (15)^2 = 293
Hence there should be 95 in place of 96.
10. 128, 320, 1120, 5040, 27720, 180190
1) 27720
2) 5040
3) 320
4) 1120
5) 180190
128 * 5/2 = 320
320 * 7/2 = 1120
1120 * 9/2 = 5040
5040 * 11/2 = 27720
27720 * 13/2 = 180180 not equal to 180190
239 – (12)^2 = 95 not equal to 96
95 + (13)^2 = 264
264 – (14)^2 = 68
68 + (15)^2 = 293
Hence there should be 95 in place of 96.
10. 128, 320, 1120, 5040, 27720, 180190
1) 27720
2) 5040
3) 320
4) 1120
5) 180190
128 * 5/2 = 320
320 * 7/2 = 1120
1120 * 9/2 = 5040
5040 * 11/2 = 27720
27720 * 13/2 = 180180 not equal to 180190
Understand easily to Quadratic Equation
many persons confuse with Quadratic Equation they know how to solve but dont know x>=y or no relation etc
it will easy when u write all four terms (both of X and both of Y) in descending order which u find QE method we have 5 option
1.x>y
2.y>x
3.x>=y
4.y>=x
5. no Relation
2.y>x
3.x>=y
4.y>=x
5. no Relation
1st of all 4 terms arrange in descending order
exp.-
exp.-
x=2,3
y=1,5
arrange it in descending order
5,3,2,1
y=1,5
arrange it in descending order
5,3,2,1
now write below it x/y
5 is y's term so
5 is y's term so
5
y
like this
y
like this
5,3,2,1
y,x,x,y
y,x,x,y
now u can get easly it is greater then or equal to or no relation
when u get
1.xxyy it means x>y
2.yyxx it means y>x
1.xxyy it means x>y
2.yyxx it means y>x
when u get
3.xxyy but 2nd and 3rd term equal
it means x>=y
exp-
x=5,3
y=3,1
5,3,3,1
x,x,y,y
here 3,3 is equal
so x>=y
3.xxyy but 2nd and 3rd term equal
it means x>=y
exp-
x=5,3
y=3,1
5,3,3,1
x,x,y,y
here 3,3 is equal
so x>=y
like this
4.yyxx but 2nd and 3rd term equal
it means y>=x
it means y>=x
5.all other will no relation e.i.
xyxy
yxyx
yxxy
xyyx
xyxy
yxyx
yxxy
xyyx
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