1. At the
start of business A invested some money. After 4 months B joined by investing
twice amount as A and after 8 months from start of business C invested thrice
amount as A invested. If the total shares of A and C is Rs 30,000, what is the
total profit received at the end of year?
Explanation:
Let A invested x for 12 months, then B for 2*x = 2x for (12-4) = 8 months, and C invested 3*x = 3x for (12-8) = 4 months. So A : B : C =
x*12 : 2x*8 : 3x*4
3 : 4 : 3
So (A+C) gets [(3+3)/(3+4+3)] * y = 30,000
Solve y = Rs 50,000
Let A invested x for 12 months, then B for 2*x = 2x for (12-4) = 8 months, and C invested 3*x = 3x for (12-8) = 4 months. So A : B : C =
x*12 : 2x*8 : 3x*4
3 : 4 : 3
So (A+C) gets [(3+3)/(3+4+3)] * y = 30,000
Solve y = Rs 50,000
A
mixture contains milk and water in the ratio 7 : 2. 9 litres of this mixture is
taken out and 5 litres of water is poured in. If the ratio of milk to water
becomes 14 : 5, what is the amount of milk originally present in the mixture?
Explanation:
Total = 7x+2x+24 = 9x+9
So 7x/(2x+5) = 14/5
Solve, x = 10
So total = 9*10 + 9 = 99 litres
So milk = 7/(7+2) * 99 = 77
Total = 7x+2x+24 = 9x+9
So 7x/(2x+5) = 14/5
Solve, x = 10
So total = 9*10 + 9 = 99 litres
So milk = 7/(7+2) * 99 = 77
The ratio
of monthly salaries of son to father is 2 : 5, and that of mother to son is 3 :
2. If son’s annual salary is Rs 3,00,000, then what is the monthly salary of
mother?
Explanation:
S : F = 2 : 5, M : S = 3 : 2
Or F/S = 5/2, and S/M = 2/3, So F : S : M = 5*2 : 2*2 : 2*3 = 10 : 4 : 6 = 5 : 2 : 3
Annual salry of son = 3,00,000 so monthly is 3,00,000/12 = 25,000
So 2/(5+2+3) * x = 25,000
Solve, x = 1,25,000
So mother’s monthly salary = 3/(5+2+3) * 1,25,000 = 37,500
S : F = 2 : 5, M : S = 3 : 2
Or F/S = 5/2, and S/M = 2/3, So F : S : M = 5*2 : 2*2 : 2*3 = 10 : 4 : 6 = 5 : 2 : 3
Annual salry of son = 3,00,000 so monthly is 3,00,000/12 = 25,000
So 2/(5+2+3) * x = 25,000
Solve, x = 1,25,000
So mother’s monthly salary = 3/(5+2+3) * 1,25,000 = 37,500
Tarun and
Varun alone can do a piece of work in 20 and 25 days respectively. In how many
days the work will be completed if they both work on alternate days starting
with Varun?
Explanation:
Tarun = 20 days, Varun = 25 days
Total work =1/20+1/25=9/100
Tarun = 20 days, Varun = 25 days
Total work =1/20+1/25=9/100
[here is a
small technique, Total work done will be 1, right, then multiply numerator till
denominator, as 9*11 =99, 9*12 = 108, as
9*12 is more than 100, so we will
consider 9*11, means 11 pairs ]
2*11(22) days work of
both = 9*11 = 99
So remaining work = 100-99 = 1
Now Varun’s turn on 23rd day, he will do remaining work(1) in 1/4 day (25*4)
So total 22 1/4 days
So remaining work = 100-99 = 1
Now Varun’s turn on 23rd day, he will do remaining work(1) in 1/4 day (25*4)
So total 22 1/4 days
How many 4
digit numbers can be made from the digits 2, 3, 5, 0, and 9 without repetition?
Explanation:
0 cannot be on first place for it to be a 4 digit number,
So for 1st digit 4choices, for second also 4 (because 0 can be placed here), then 3 for third place, 2 for fourth place
Total numbers = 4*4*3*2
0 cannot be on first place for it to be a 4 digit number,
So for 1st digit 4choices, for second also 4 (because 0 can be placed here), then 3 for third place, 2 for fourth place
Total numbers = 4*4*3*2
476,
480, 479, 495, 490, 522, 497
Explanation:
476 + 2^2, 480 – 1^2, 479 + 4^2, 495 – 3^2, 486 + 6^2, 522 – 5^2, 497
476 + 2^2, 480 – 1^2, 479 + 4^2, 495 – 3^2, 486 + 6^2, 522 – 5^2, 497
SO, Here Ans come 490
11, 18,
35, 80, 159, 286
Explanation:
18 – 11 = 7, 37 – 18 = 19, 80 – 37 = 43, 159 – 80 = 79, 286 – 159 = 127
19 – 7 = 12, 43 – 19 = 24, 79 – 43 = 36, 127 – 79 = 48 (Double Series)
18 – 11 = 7, 37 – 18 = 19, 80 – 37 = 43, 159 – 80 = 79, 286 – 159 = 127
19 – 7 = 12, 43 – 19 = 24, 79 – 43 = 36, 127 – 79 = 48 (Double Series)
SO, Here Ans come 35
112,
224, 280, 308, 322, 330
Explanation:
112+(112/1), 224+(112/2), 280+(112/4), 308+(112/8), 322+(112/16), 329
112+(112/1), 224+(112/2), 280+(112/4), 308+(112/8), 322+(112/16), 329
SO, Here Ans come 330
444, 440, 431, 420, 390,
354
Explanation:
444 – 2^2, 440 – 3^2, 431 – 4^2, 415 – 5^2, 390 – 6^2, 354
444 – 2^2, 440 – 3^2, 431 – 4^2, 415 – 5^2, 390 – 6^2, 354
SO, Here Ans come 420
24, 12,
18, 45, 157.25, 708.75
Explanation:
24*0.5, 12*1.5, 18*2.5, 45*3.5, 157.5*4.5, 708.75
24*0.5, 12*1.5, 18*2.5, 45*3.5, 157.5*4.5, 708.75
SO, Here Ans come 157.25
Study
the given line graph carefully and answer the questions that follow.
The graph given below shows the number of employees in two departments of company ABC from year 2010 to 2015.

The graph given below shows the number of employees in two departments of company ABC from year 2010 to 2015.

In
which year is the percentage increase in the number of employees over the
previous year the highest for IT department?
Explanation:
In 2011, % increase is (2600-1800)/1800 * 100 = 44.4%
In 2012, 2013 the number is decreasing
In 2014, % increase is (2050-1950)/1950 * 100 = 5.12%
In 2015, % increase is (2200-2050)/2050 * 100 = 7.3%
In 2011, % increase is (2600-1800)/1800 * 100 = 44.4%
In 2012, 2013 the number is decreasing
In 2014, % increase is (2050-1950)/1950 * 100 = 5.12%
In 2015, % increase is (2200-2050)/2050 * 100 = 7.3%
Number
of employees in HR department is approximately what percentage of the total
number of employees in both departments together in the year 2014?
Explanation:
In 2014, in HR = 1200
In HR + IT = 1200 + 2050 = 3250
So required % = (1200/3250)*100 = 36.9
In 2014, in HR = 1200
In HR + IT = 1200 + 2050 = 3250
So required % = (1200/3250)*100 = 36.9
What is
the average number of employees in IT Department over all years?
Explanation:
1800+2600+2400+1950+2050+2200 / 6 = 2166
1800+2600+2400+1950+2050+2200 / 6 = 2166
Number
of employees in HR department in 2012 is what percent less than that of IT
department in the same year?
Explanation:
(2400-1900)/2400] * 100 = 20.8%
(2400-1900)/2400] * 100 = 20.8%
What is
the difference between the averages of number of employees in both departments
for all the years?
Explanation:
Average in IT department = 1800+2600+2400+1950+2050+2200 / 6 = 2166
Average in HR department = 1400+2700+1900+2100+1200+1500 / 6 = 1800
Difference = 2166-1800 = 366
Average in IT department = 1800+2600+2400+1950+2050+2200 / 6 = 2166
Average in HR department = 1400+2700+1900+2100+1200+1500 / 6 = 1800
Difference = 2166-1800 = 366
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