Quants

Ratio of A’s age four years ago and B’s age four years ago was 5 : 8. A’s age 6 years after will be 6 less than B’s present age. Find the ratio of the present ages of A and B.
Explanation: 
4 yrs ago, A-4/B-4 = 5/8 8A – 5B = 12
 After 6 yrs, A + 6 = B – 6 
Solve the equations, A = 24, B = 36
So,2:3

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Quants

 Directions (1-5): Study the following pie-charts and answer the questions that follow: There are 5 sections in a class with given information in the pie-char

1. Find the ratio of the total number of students in sections C and D to number of males in the same sections. 

Explanation:

 Students in C and D = (15+13)/100 * 2400 = 672

 No of males in C and D = (6+20)/100 * 1300 = 338

 So ratio = 672 : 338 = 336 : 169

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Quants

What will come in place of (?) in the following series?

1. 6, 4, 5, 11, 39, 189, ?
   A) 1039
   B) 1127
   C) 1150
   D) 1129
   E) 1189

B) 1127
Explanation: 
6*1 – 2, 4*2 – 3, 5*3 – 4, 11*4 – 5, 39*5 – 6, 189*6 – 7

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Quants

The ratio of present ages of A and B is 2 : 3. 6 years hence, the ratio of their ages will be 13 : 18. Find 2/5th of B’s age.

Explanation:

 Let the present ages of A and B are 2x and 3x 

After 6 years, 2x+6 / 3x+6 = 13/18 

Solve, x = 10 B’s age = 30, 

2/5 * 30 = 12

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Quants

Ten years ago, A’s age was half that of B. If the ratio of the present ages of A and B is 3 : 5, find the total of their present ages. 
Let the present ages of A and B are 3x and 5x.
Then, 10 yrs ago, (3x-10) = ½ * (5x-10)
Solve, x = 10
So present ages of A and B are 30 and 50 resp, their sum = 80

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Numerical Ability

 There are two mixtures A and B containing water and milk. A contains 20% water and B contains 30% water. Some quantity is taken from A and double this quantity from B, they are mixed to form another mixture C. What is the percentage of milk in mixture C?

• Let x litres taken from mixture A, then 2x litres from mixture B. So ratio of milk to water in mixture C =
  80% of x + 70% of 2x : 20% of x + 30% of 2x
  = (80/100) + (140/100) : (20/100) + (60/100)
  = 11 : 4
  So % of milk = [11/(11+4)] * 100=73.33%

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Maths

Distance between point P and Q is 480 km. A train starts from point P at 6:00 AM with 60 km/hr towards Q. Another train starts from point Q towards P at 7:00 AM with 80 km/kr. At what time the trains will meet?

Explanation:

When 2^nd train starts i.e. at 7 AM (1 hr after 6 AM), distance covered by first train is 60 km (i.e. in 1 hr).
Now 2^nd train also starts and distance between them is now (480-60) = 420 km
Both coming in opposite direction, so relative speed = (60+80) = 140 km/hr
So time = 7:00 AM + (420/140) = 7:00 AM +3 hrs = 10:00 AM

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Numerical Ability

1.  At the start of business A invested some money. After 4 months B joined by investing twice amount as A and after 8 months from start of business C invested thrice amount as A invested. If the total shares of A and C is Rs 30,000, what is the total profit received at the end of year?

Explanation:
Let A invested x for 12 months, then B for 2*x = 2x for (12-4) = 8 months, and C invested 3*x = 3x for (12-8) = 4 months. So A : B : C =
x*12 : 2x*8 : 3x*4
3 : 4 : 3
So (A+C) gets [(3+3)/(3+4+3)] * y = 30,000
Solve y = Rs 50,000

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Numerical Ability Quiz

Rice is bought at the rate of Rs 8 per kg. Out of the total quantity of 110 kg, 60 kg of rice is sold at 10% profit. At what rate per kg the remaining need rice need to be sold so that there is a profit of 20% on the total price?

Explanation:
Let remaining (110-60) = 50 kg at x%. So by allegation method,
(60 kg)…………………(50 kg)
10% …………………….x%
…………….20%
(x-20)…………..………10
So (x-20)/10 = 60 kg/50 kg
Solve, x = 32%
50 kg costs = 50*8 = Rs 400
So at 32% profit SP of 50 kg is (132/100) * 400 = Rs 528
So SP of 1 kg = 528/50 = 10.56

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Number series

Ques 1.      3,  3,  4.5,   ..........,   22.5,     67.5 ?

a) 13.5

b) 8.5

c) 9.0

d) 10.5

e) None of The Above

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Double diagramme set

Study the following pie chart and table to answer these questions.

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Quadratic Equation

Understand easily to

many persons confuse with Quadratic Equation they know how to solve but dont know x>=y or no relation etc

it will easy when u write all four terms (both of X and both of Y) in descending order which u find QE method we have 5 option

1.x>y
2.y>x
3.x>=y
4.y>=x
5. no Relation

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Quant Quiz

1. ? % of 824 + 244 = 1480
1) 140
2) 150
3) 100
4) 180
5) 120

2. 24.5 × 8.4 × 16 = ?
1) 3292.8
2) 3492.8
3) 3294.8
4) 3192.8
5) 3094.8

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Data sufficiency

Introduction
    Data sufficiency has recently become a favorite question for many of the recent examinations. In this type of questions, usually a question is given followed by two or three statements. These two or three statements contain data or some pieces of information using which the question can possibly be solved. You are required to judge whether the data given is sufficient to answer the question or not.
fORMAT OF sTUDY

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Permutation and Combination

Permutation: The different arrangements of a given number or things by taking some or all at a time , are called Permutations.
 All permutations (or arrangements) made with the letters of a, b, c by taking two at a time are ( ab, ba, ac, ca, bc, cb )
All permutations made with the letters a, b, c, taking all at a time are: ( abc, acb, bac, bca, cab, cba ).

Number of Permutations: Number of all permutations of n things, taken r at a time, is given by:
n p r = n ( n – 1 ) ( n – 2 )……(n – r + 1 ) = n! / ( n – r ) !
Ex.6 p 2
= ( 6 x 5 ) = 30 .
Ex.7 p 3
= ( 7 x 6 x 5 ) = 210 ;
Note: Number of all permutation that is n things, we can take all at a time = n!

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Probability

Experiment:
The actions of that Appear some well-defined outcomes is called an Experiment.

Random Experiment:
An Random experiment is an experiment in which all probable outcomes are known and we cannot predicted the accurate in advances that is called Random Experiment.

Here is some example for your better perceive about Random experiment.
When we throw a coin on the air, The coin either a Head (H) or a Tail (T)appears.
When we throw a dice is a solid cube, having 6 faces, marked 1, 2, 3, 4, 5, 6 gradually. In that case when we throw a dice the outcome is the number that appears on its upper face of the dice

Sample Space:
Sample Space is an set S of all possible outcomes in a particular actions.

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Problems on trains

There are train based problem based on two object, First is Train and second object is that which is crossed by the train.

Some important Facts

• If a train moving or cross a pole or man than the first object is train and the second object is pole or man.
• If the train moving or cross the platform than the first object is train and second object is platform which is train cross.
• If a train cross or moving a man who is standing on platform than the train is first object and the second object is man.
• When a train crossing or moving another train in the same direction or opposite direction than the first object is first train and second object is second train.

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Mixture and allegation

Alligation: This is the rule that enables us to find the ratio in which two or more ingredients at the given price must be mixed to produce a mixture of a desired price. Mean Price: The cost Price of a unit quantity of the mixture is called the mean price.
 Rule of Alligation:

If Two ingredients are mixed in a ratio , then
Quantity of cheaper/Quantity of dealer =C.P dealer-Mean price/Mean price-C.P Cheaper    

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INEQUALITY

What is Variables?
An element, a feature, or a factor that is liable to vary or change to find any equation and represent by x, y, z etc.
Example: 3x + 27y = 40 is variable
Example: 2y + 5x = 12 is variable.

What is Constant?
A constant is special number or a real number usually or whose value is fixed in the context of use is called a constant.
Example: 5x – 3y + 2z = 24 here is 5, 3, 2, 24 are constant value.
Example: 4y + 7y – 9z = 53 here is 4, 7, 9, 53 are constant value.

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Speed, Time and distance

Basic Formula of speed and distance
Distance = Speed x Time
Speed = Distance / Time
Time = Distance / Speed
1 km. /hour =5/18 m. /sec
1 m. /sec = 18/5 km. /hour

Arjun goes to his college from his house at a speed of 3 Km / hr and return at speed of 2 km / hr. If he takes 5 hours in going and coming, the distance between his house and college is-

Average speed = (2*3*2/2+3) km / hr =12/5 km / hr.
Distance between his house and college he travelled : (12/5x 5 ) km = 12 km .

How many minutes does Seema take to cover a distance of 600 m, if she runs at speed of 40 km / hr ?

Seema speed = 40 km / hr,.
(40 x5/18) = 100/9 m / sec     (after converting it into m / sec)
So, Seema Time taken to cover 600 m = (600 x9/100) sec = 54 sec.

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