1. 73% of 8523 + 32% of 6245 = ?
a) 8042.21
b) 8136.28
c) 8625.35
d) 8220.19
e) None of these
? = 73% of 8523 + 32% of 6245
? = 8523 × + 6245 ×
= 6221.79 + 1998.40 = 8220.19
2. ૩√804357 = ?
a) 93
b) 76
c) 83
d) 86
e) None of these
Option A
? = √804357
= √93 × 93 × 93
= 93
3. 8226 ÷ 15 ÷ 5 = ?
a) 2156
b) 109.68
c) 185.56
d) 2742
e) None of these
4. 182.225 × 21.652 × 33.584 = ?
a) 132507
b) 149428
c) 120426
d) 106438
e) 112642
5. 63.5% of 8924.2 + ?% of 5324.4 = 6827.5862
a) 36
b) 22
c) 17
d) 31
e) 9
. of 8924.2 + ? of 5324.4 = 6827.5862
8924 × + 5325 × ? = 6828
5711 + × ? = 6828
? = × = = 22 (approx.)
Directions (Q. 6-10) Study the information carefully and answer the questions that follow.
A school has a total of 1200 students. The ratio of girls to boys in the school is 3:2. All the
students have enrolled in hobby classes viz. Singing, Dancing, Martial Arts and Cooking. One-twelfth of the boys have enrolled in only cooking classes. 25% of the girls have enrolled in Cooking and Singing classes together. Number of boys enrolled in only Martial Arts classes is 150% of the number of girls enrolled in the same. Number of students enrolled in only Dancing is 26% of the total number of students. 5% of the girls have enrolled in only Martial Arts classes. One-third of the boys enrolled in only Dancing classes. 35% of the girls enrolled in Singing, dancing and Martial Arts together and the remaining enrolled in only Cooking. 15% of the boys enrolled in Cooking and Singing classes together and the remaining enrolled in Singing, Dancing and Martial Arts classes together.
Total number of students = 1200
Total number of girls = 1200 ×3/5=720
Total number of boys = 1200-720 = 480
Number of boys enrolled in only cooking = 1/12× 480 = 40
Number of girls enrolled in cooking and singing together = 25%× 720
Number of students enrolled in only dancing classes = 1200 ×26% = 312
Number of girls enrolled in only martial arts classes = 720 ×5% = 36
Number of boys enrolled in only martial arts classes = 36 ×150% = 54
Number of boys enrolled in only dancing classes =1/3 × 480 = 160
Number of girls enrolled in singing, dancing and martial arts classes together =720 ×35/100 = 252
Number of girls enrolled in only cooking classes = 720 – 252 = 468
Number of boys enrolled in cooking and singing classes = 480×15/100 = 72
Number of boys enrolled in singing, dancing and martial arts classes = 480 – 72 = 408
6. Number of boys enrolled in Cooking and Singing classes together is what percent of the girls
enrolled in the same?
a) 48
b) 36
c) 20
d) 25
e) None of these (40)
7. What is the total number of students learning Martial Arts?
a) 96
b) 496
c) 342
d) 128
e) None of these= 36 + 54 = 90
8. How many girls are enrolled in only Cooking classes?
a) 280
b) 252
c) 154
d) 100
e) None of these=468
9. How many boys learn Singing?
a) 226
b) 184
c) 72
d) 96
e) None of these
Number of boys who learning singing
= 480 – (40 + 54 + 160)
= 480 – 254 = 226
10. What is the respective ratio of girls to boys enrolled in only Dancing classes?
a) 8:7
b) 14:17
c) 19:20
d) 12:7
e) None of these
Required ratio = = 152:160 = 19:20
11. In how many different ways can the letters of the word ‘FLEECED’ be arranged?
a) 840
b) 2520
c) 1680
d) 49
e) None of these
= 7 × 6 × 5 × 4 = 840
12. The perimeter of a square is 164 metres. What is the area of the square?
a) 1089 sq. metres
b) 1764 sq. metres
c) 1661 sq. metres
d) 1681 sq. metres
e) None of these
Area of the square = 164/4 square = 41 = 1681 sq. m
13. The product of two successive numbers is 1980. Which is the smaller number?
a) 34
b) 44
c) 35
d) 45
e) None of these
X × (x + 1) = 1980
+ x – 1980 = 0
+ 45x – 44x – 1980 = 0
x (x + 45) – 44 (x + 45) = 0
(x – 44) (x + 45) = 0
x = 44, smallest number is 44
14. The difference between 55% of a number and 25% of the same number is 11.10. What is 75%
of that number?
a) 27.75
b) 37
c) 21.25
d) 45
e) None of these
(11.10*100/55-25)*75/100= 27.75
15. The average of the ages of 3 friends is 23. Even if the age of 4th friend is added the average
remains 23. What is the age of 4th friend?
a) 32
b) 21
c) 23
d) Cannot be determined
e) None of these
16. 8 men working for 9 hours a day complete a piece of work in 20 days. In how many days can
7 men working for 10 hours a day complete the same piece of work?
a) 21 days
b) 20-3/5 days
c) 20-1/2 days
d) 21-3/7 days
e) None of these
M H D
8 9 20
7 10 x
8*9*20/7*10*X
X=8*9*20/7*10
= 20-4/7 days
17. If 12a + 12b = 45, what is the average of a and b ?
a) 3.75
b) 1.875
c) 3.875
d) 1.75
e) None of these
12a + 12b = 45
a+b=45/12
Now avg find, a+b/2=45/12*2= 1.875
18. How much part of a day is 45 minutes?
a) 1/42
b) 1/24
c) 1/32
d) 1/48
e) None of these
Here ,60 minutes And 24 hours so divided that
45/60*24=1/32
19. Samir drove at the speed of 45 km from home to a resort. Returning over the same route, he
got stuck in traffic and took an hour longer, also he could drive only at the speed of 40 km.
How many kilometres did he drive each way?
a) 250 km
b) 300 km
c) 310 km
d) 275 km
e) None of these
x/45-x/40=1
So,Here Solve to equation X=360
20. What is the greater of two numbers whose product is 640, if the sum of the two numbers,
exceeds their difference by 32 ?
a) 45
b) 50
c) 55
d) 40
e) None of these
Suppose two numbers are x and y.
xy = 640
(x + y) – (x – y) = 32
x + y – x + y = 32
2y = 32
y = 16
x × 16 = 640
x = 640/16=400
largest number is 40
21. On a test consisting of 150 questions, Rita answered 40% of the first 75 questions correctly.
What percent of the other 75 questions does she need to answer correctly for her grade on the
entire exam to be 60%?
a) 80
b) 70
c) 40
d) 50
e) None of these
Directions (Q. 22-26) Each of the questions below consists of a question and two statements
numbered I and II given below it. You have to decide whether the data provided in the statements are
sufficient to answer the question. Read both the statements and
Give answer (1) if the data in Statement I alone are sufficient to answer the question, while the data in
Statement II alone are not sufficient to answer the question.
Give answer (2) if the data in Statement II alone are sufficient to answer the question, while the data
in Statement I alone are not sufficient to answer the question.
Give answer (3) if the data either in Statement I alone or in Statement II alone are sufficient to answer
the question.
Give answer (4) if the data in both the Statements I and II are not sufficient to answer the question.
Give answer (5) if the data in both the Statements I and II together are necessary to answer the
question.
22. What is the speed of the bus?
I. The bus covers a distance of 80 km in 5 h.
II. The bus covers a distance of 160 km in 10 h.
(3) if the data either in Statement I alone or in Statement II alone are sufficient to answer
the question.
From statement I, speed of bus =80/5 = 16 km/h
From statement II, speed of bus =160/16= 16 km/h
23. What is the ratio of the number of freshers to the number of seniors in a college?
I. The ratio of males and females in the college is 2:3.
II. There are 1125 female freshers in the college.
if the data in both the Statements I and II are not sufficient to answer the question.
24. What is Mr.Mehta’s present income?
I. Mr.Mehta’s income increases by 10% every year.
II. His income will increase by Rs.2500 this year.
if the data in both the Statements I and II together are necessary to answer the
From statements I and II, Present income of Mr.Mehta = 2500×100/10 = Rs.25000
25. What is Nidhi’s age?
I. Nidhi is 3 times younger to Rani.
II. Surekha is twice the age of Rani and the sum of their ages is 72.
if the data in both the Statements I and II together are necessary to answer the
From statement II, age of Rani =72×1/3 = 24 years
From statement I, age of Nidhi =24 ×1/3 = 8 years
26. What is the ratio of the total number of girls to the total number of boys in the school?
I. The ratio of the total number of boys to the total number of girls, last year was 4:5.
II. There are 3500 students in the school out of which 60% are boys.
if the data in Statement II alone are sufficient to answer the question, while the data
in Statement I alone are not sufficient to answer the question.
From statement II, number of boys = 60%
Number of girls = 40%
Required ratio = 60 : 40 = 3 : 2
27. In a class of 80 students and 5 teachers, each student got sweets that are 15% of the total
number of students and each teacher got sweets that are 25% of the total number of students.
How many sweets were there?
a) 1030
b) 1040
c) 1050
d) 1060
e) None of these
Total number of sweets = 80 ×15/100 of 80 + 5 × 80 ×25/100
= 960 + 100 = 1060
28. The product of two successive even numbers is 6888. Which is the greater of the two
numbers?
a) 78
b) 82
c) 86
d) 90
e) None of these
Suppose the greater number is x
x (x – 2) = 6888
X2– 2x – 6888 = 0
X2– 84x + 82x – 6888 = 0
x (x – 84) + 82 (x – 84) = 0
(x – 84) (x + 82) = 0
x = 84 or −82
the greater number is 84
29. By how much 7/9th of 234 lesser than 10/13th of 247?
a) 12 b) 26 c) 38
d) 14 e) None of these
30. Bhawna decided to donate 12% of her salary to an Orphanage. On the day of donation she
changed her mind and donated Rs.2400 which was 125% of what she had decided earlier.
How much is Bhawna’s salary?
a) Rs.14750
b) Rs.16000
c) Rs.18500
d) Can’t be determined
e) None of these
31. Gaurav spent Rs.38460 on the renovation of his home, Rs.24468 on buying home theater and
the remaining 28% of the total amount he had as cash with him. What was the total amount?
a) Rs.92600
b) Rs.76500
c) Rs.87400
d) Can’t be determined
e) None of these
32. Which number should replace both the question marks in the following equation?
!/944=59/!
a) 218
b) 236
c) 244
d) 264
e) None of these
(10/13 of 247) – ( 7/9of 234) = 190 – 182 = 8
33. The ages of Ranjana and Rakhi are in the ratio of 15:17 respectively. After 6 years the ratio of
their ages will be 9:10. What will be the age of Ranjana after 6 years?
a) 40 years
b) 30 years
c) 34 years
d) 36 years
e) None of these
Suppose the age of Ranjana and Rakhi is 15x years and 17x years.
After 6 years the age of Ranjana and Rakhi
15x+6/17x+6=9/10
153x + 54 = 150x + 60
153x – 150x = 60 – 54
3x = 6x = 2
So, the age of Ranjana after 6 years = 15 × 2 + 6 = 36 years
34. One-seventh of a number is 38. What will 63% of that number be?
a) 174.56
b) 189.42
c) 167.58.
d) 204.32
e) None of these
35. The simple interest accrued on an amount of Rs.17000 at the end of four years is Rs.6800.
What would be the compound interest accrued on the same amount at the same rate in the
same period?
a) Rs.7889.7
b) Rs.8324
c) Rs.6990.5
d) Can’t be determined
e) None of these
36. What will be the area (in square metre) of 1.5 m wide garden developed around all the four
sides of a rectangular field having area equal to 300 sq. m and breadth equal to three-fourth of
the length?
a) 96
b) 105
c) 114
d) Can’t be determined
e) None of these
Suppose the length of the field is 3x/4 m.
So, the breadth of the field will be m
x ×3x/4 = 300
x2= 300×4/3 = 400
x = √400
x = 20
Area of the garden = (20 + 3) (15 + 3) – 300
= (23) (18) – 300 = 114 square metre
37. In a two digit positive number, the digit in the units place is equal to the square of the digit in
ten’s place, and the difference between the number and the number obtained by interchanging
the digits is 54. What is 40% of the original number?
a) 15.6
b) 39
c) 37.2
d) 24
e) None of these
38. Vishwas borrowed a total amount of Rs.30000, part of it on simple interest rate of 12% per
annum and remaining on simple interest rate of 10% per annum. If at the end of 2 years he
paid in all Rs.36480 to settle the loan amount, what was the amount borrowed at 12% per
annum?
a) Rs.16000
b) Rs.18000
c) Rs.17500
d) Rs.12000
e) None of these
39. If the numerator of a fraction is increased by ¼ and the denominator is decreased by 1/3 the
new fraction obtained is 33/64. What was the original fraction?
a) 9/11
b) 5/7
c) 3/7
d) 7/9
e) None of these
40. Twice the square of a number is more than eleven times the number by 21. The number can
have which of the following values?
a) 4 or -7/2
b) 7 or -3/2
c) 3 or -7/2
d) 9/2 or -4
e) None of these
Suppose the number is x.
2 – 11x = 21
2 – 11x – 21 = 0
2 – 14x + 3x – 21 = 0
2x (x – 7) + 3 (x – 7) = 0
(x – 7) (2x + 3) = 0
x = 7 or −3/2


